Erratum for “Improved Methods of Parameterization for Estimating the Magnitude and Frequency of Peak Discharges in Rural Ungaged Streams” by C. C. Hodges, W. M. McDonald, R. L. Dymond, and K. L. Hancock

Hodges, C. C.; McDonald, W. M.; Dymond, R. L.; Hancock, K. L.

doi:10.1061/(ASCE)HE.1943-5584.0001364

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Mar 2, 2016

Erratum for “Improved Methods of Parameterization for Estimating the Magnitude and Frequency of Peak Discharges in Rural Ungaged Streams” by C. C. Hodges, W. M. McDonald, R. L. Dymond, and K. L. Hancock

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Authors: C. C. Hodges, M.ASCE [email protected], W. M. McDonald, S.M.ASCE [email protected], R. L. Dymond, M.ASCE [email protected], and K. L. Hancock, A.M.ASCE [email protected]Author Affiliations

Publication: Journal of Hydrologic Engineering

Volume 21, Issue 5

https://doi.org/10.1061/(ASCE)HE.1943-5584.0001364

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In Tables 3–6 of the final published paper, during the review process, an incorrect conversion factor was applied in the equations when converting from English units to SI units. The corrected SI unit equations are given in the tables below:

Table 3. Regression Results for Complete Data Set

Return period	Comprehensive analysis				Drainage area only
Return period	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations
2 year	29.86	97.77	28.76	$Log 10 (0.5 peak) = 2.515 + 0.814 \times Log 10 (DA) + 0.826 \times Log 10 (FSl) - 0.738 \times Log 10 (ME)$	38.39	96.29	37.63	$Log 10 (0.5 peak) = - 0.135 + 0.838 \times Log 10 (DA)$
5 year	33.96	96.96	32.64	$Log 10 (0.2 peak) = 2.895 + 0.79 \times Log 10 (DA) + 0.655 \times Log 10 (FSl) - 0.807 \times Log 10 (ME)$	40.17	95.7	39.28	$Log 10 (0.2 peak) = 0.179 + 0.806 \times Log 10 (DA)$
10 year	39.19	95.85	37.66	$Log 10 (0.1 peak) = 3.06 + 0.779 \times Log 10 (DA) + 0.574 \times Log 10 (FSl) - 0.834 \times Log 10 (ME)$	42.32	95.09	41.3	$Log 10 (0.1 peak) = 0.346 + 0.789 \times Log 10 (DA)$
25 year	45.11	94.4	43.3	$Log 10 (0.04 peak) = 3.215 + 0.766 \times Log 10 (DA) + 0.472 \times Log 10 (FSl) - 0.854 \times Log 10 (ME)$	47.75	93.67	46.59	$Log 10 (0.04 peak) = 0.523 + 0.772 \times Log 10 (DA)$
50 year	45.59	93.19	47.55	$Log 10 (0.02 peak) = 3.298 + 0.759 \times Log 10 (DA) + 0.405 \times Log 10 (FSl) - 0.863 \times Log 10 (ME)$	52	92.37	50.65	$Log 10 (0.02 peak) = 0.638 + 0.76 \times Log 10 (DA)$
100 year	55.59	91.34	53.65	$Log 10 (0.01 peak) = 2.366 + 0.763 \times Log 10 (DA) - 0.596 \times Log 10 (ME)$	56.12	91.09	54.62	$Log 10 (0.01 peak) = 0.741 + 0.751 \times Log 10 (DA)$
200 year	60.73	89.74	58.56	$Log 10 (0.005 peak) = 2.619 + 0.756 \times Log 10 (DA) - 0.653 \times Log 10 (ME)$	62.09	89.17	60.43	$Log 10 (0.005 peak) = 0.825 + 0.743 \times Log 10 (DA)$
500 year	67.83	87.46	65.37	$Log 10 (0.002 peak) = 2.913 + 0.748 \times Log 10 (DA) - 0.722 \times Log 10 (ME)$	69.05	86.88	67.16	$Log 10 (0.002 peak) = 0.939 + 0.733 \times Log 10 (DA)$

Note: DA = drainage area ( ${km}^{2}$ ); FSl = focal slope ( $m / m$ ); ME = mean elevation (m); SME = standard model error; Sp = average standard error of prediction; Sp, Pseudo- $R^{2}$ , and SME are computed using Log10(Peak); Peak flows given in $m^{3} / s$ .

Table 4. Regression Results for Stations with Drainage Areas Less Than

64.8 {km}^{2}

(

25 {mi}^{2}

)

Return period	Comprehensive analysis				Drainage area only
Return period	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations
2 year	38.17	89.66	34.95	$Log 10 (0.5 peak) = - 4.979 + 0.799 \times Log 10 (DA) + 0.874 \times Log 10 (FSl) - 0.711 \times Log 10 (ME) + 4.035 \times Log 10 (CN)$	55.19	77.66	53.03	$Log 10 (0.5 peak) = - 0.068 + 0.75 \times Log 10 (DA)$
5 year	44.27	86.67	40.41	$Log 10 (0.2 peak) = - 6.63 + 0.803 \times Log 10 (DA) + 0.744 \times Log 10 (FSl) - 0.696 \times Log 10 (ME) + 5.008 \times Log 10 (CN)$	59.19	75.27	56.65	$Log 10 (0.2 peak) = 0.211 + 0.751 \times Log 10 (DA)$
10 year	51.98	82.79	47.33	$Log 10 (0.1 peak) = - 7.452 + 0.807 \times Log 10 (DA) + 0.667 \times Log 10 (FSl) - 0.676 \times Log 10 (ME) + 5.478 \times Log 10 (CN)$	64.85	72.02	61.87	$Log 10 (0.1 peak) = 0.36 + 0.754 \times Log 10 (DA)$
25 year	67.14	73.46	62.88	$Log 10 (0.04 peak) = - 9.333 + 0.786 \times Log 10 (DA) + 5.331 \times Log 10 (CN)$	74.14	67.24	70.48	$Log 10 (0.04 peak) = 0.517 + 0.761 \times Log 10 (DA)$
50 year	74.12	70.54	69.24	$Log 10 (0.02 peak) = - 9.956 + 0.793 \times Log 10 (DA) + 5.724 \times Log 10 (CN)$	82.16	63.48	77.92	$Log 10 (0.02 peak) = 0.615 + 0.766 \times Log 10 (DA)$
100 year	82.21	67.43	76.6	$Log 10 (0.01 peak) = - 10.499 + 0.801 \times Log 10 (DA) + 6.07 \times Log 10 (CN)$	90.59	60.12	85.71	$Log 10 (0.01 peak) = 0.713 + 0.772 \times Log 10 (DA)$
200 year	91.08	64.27	84.64	$Log 10 (0.005 peak) = - 10.992 + 0.808 \times Log 10 (DA) + 6.379 \times Log 10 (CN)$	99.9	56.8	94.29	$Log 10 (0.005 peak) = 0.79 + 0.779 \times Log 10 (DA)$
500 year	104.1	60.29	96.4	$Log 10 (0.002 peak) = - 11.567 + 0.819 \times Log 10 (DA) + 6.746 \times Log 10 (CN)$	113.7	52.54	107	$Log 10 (0.002 peak) = 0.896 + 0.788 \times Log 10 (DA)$

Note: CN = curve number; DA = drainage area ( ${km}^{2}$ ); FSl = focal slope ( $m / m$ ); ME = mean elevation (m); SME = standard model error; Sp = average standard error of prediction; Sp, Pseudo- $R^{2}$ , and SME are computed using Log10(Peak); Peak flows given in $m^{3} / s$ .

Table 5. Regression Results for Stations with Drainage Areas Greater Than

64.8 {km}^{2}

(

25 {mi}^{2}

)

Return period	Comprehensive analysis				Drainage area only
Return period	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations
2 year	19.06	96.39	17.79	$Log 10 (0.5 peak) = 3.319 + 0.828 \times Log 10 (DA) + 0.768 \times Log 10 (FSl) - 0.795 \times Log 10 (ME) - 0.225 \times Log 10 (MTt)$	23.8	93.92	23.08	$Log 10 (0.5 peak) = 0.166 + 0.739 \times Log 10 (DA)$
5 year	20.38	95.82	18.88	$Log 10 (0.2 peak) = 4.348 + 0.856 \times Log 10 (DA) + 0.683 \times Log 10 (FSl) - 1.028 \times Log 10 (ME) - 0.318 \times Log 10 (MTt)$	25.35	92.86	24.81	$Log 10 (0.2 peak) = 0.435 + 0.718 \times Log 10 (DA)$
10 year	22.38	95.02	20.65	$Log 10 (0.1 peak) = 4.922 + 0.871 \times Log 10 (DA) + 0.649 \times Log 10 (FSl) - 1.162 \times Log 10 (ME) - 0.366 \times Log 10 (MTt)$	28.5	91.27	27.54	$Log 10 (0.1 peak) = 0.59 + 0.706 \times Log 10 (DA)$
25 year	26.07	93.42	24.04	$Log 10 (0.04 peak) = 5.565 + 0.888 \times Log 10 (DA) + 0.614 \times Log 10 (FSl) - 1.31 \times Log 10 (ME) - 0.42 \times Log 10 (MTt)$	32.71	88.78	31.58	$Log 10 (0.04 peak) = 0.745 + 0.694 \times Log 10 (DA)$
50 year	28.6	92.27	26.34	$Log 10 (0.02 peak) = 5.98 + 0.899 \times Log 10 (DA) + 0.594 \times Log 10 (FSl) - 1.409 \times Log 10 (ME) - 0.455 \times Log 10 (MTt)$	36.36	86.49	35.11	$Log 10 (0.02 peak) = 0.838 + 0.687 \times Log 10 (DA)$
100 year	31.6	90.81	29.12	$Log 10 (0.01 peak) = 6.355 + 0.911 \times Log 10 (DA) + 0.573 \times Log 10 (FSl) - 1.498 \times Log 10 (ME) - 0.488 \times Log 10 (MTt)$	40.41	83.86	39.04	$Log 10 (0.01 peak) = 0.93 + 0.681 \times Log 10 (DA)$
200 year	35.07	89.04	32.36	$Log 10 (0.005 peak) = 6.71 + 0.924 \times Log 10 (DA) + 0.548 \times Log 10 (FSl) - 1.581 \times Log 10 (ME) - 0.523 \times Log 10 (MTt)$	44.55	81.18	43.05	$Log 10 (0.005 peak) = 1.012 + 0.676 \times Log 10 (DA)$
500 year	40.19	86.1	37.55	$Log 10 (0.002 peak) = 5.636 + 0.982 \times Log 10 (DA) - 1.243 \times Log 10 (ME) - 0.613 \times Log 10 (MTt)$	50.28	77.41	48.6	$Log 10 (0.002 peak) = 1.105 + 0.67 \times Log 10 (DA)$

Note: DA = drainage area ( ${km}^{2}$ ); FSl = focal slope ( $m / m$ ); ME = mean elevation (m); MTt = mean travel time (min); SME = standard model error; Sp = average standard error of prediction; Sp, Pseudo- $R^{2}$ , and SME are computed using Log10(Peak); Peak flows given in $m^{3} / s$ .

Table 6. Regression Results for Stations with Drainage Areas Less Than

25.9 {km}^{2}

(

10 {mi}^{2}

)

Return period	Comprehensive analysis				Drainage area only
Return period	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations	Sp (%)	Pseudo- $R^{2}$	SME (%)	Equations
2 year	42.59	82.46	38.64	$Log 10 (0.5 peak) = - 7.642 + 0.673 \times Log 10 (FSl) + 4.476 \times Log 10 (CN) + 0.758 \times Log 10 (IA)$	58.49	65.87	55.43	$Log 10 (0.5 peak) = - 0.009 + 0.654 \times Log 10 (DA)$
5 year	50.1	77.9	45.25	$Log 10 (0.2 peak) = - 9.741 + 0.472 \times Log 10 (FSl) + 5.697 \times Log 10 (CN) + 0.757 \times Log 10 (IA)$	61.11	65.48	57.57	$Log 10 (0.2 peak) = 0.26 + 0.682 \times Log 10 (DA)$
10 year	58.13	72.02	53.4	$Log 10 (0.1 peak) = - 10.262 + 5.886 \times Log 10 (CN) + 0.735 \times Log 10 (IA)$	66.42	62.92	62.29	$Log 10 (0.1 peak) = 0.402 + 0.701 \times Log 10 (DA)$

Note: CN = curve number; DA = drainage area ( ${km}^{2}$ ); FSl = focal slope ( $m / m$ ); IA = isochronal area ( ${km}^{2}$ ); SME = standard model error; Sp = average standard error of prediction; Sp, Pseudo- $R^{2}$ , and SME are computed using Log10(Peak); Peak flows given in $m^{3} / s$ .

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Journal of Hydrologic Engineering

Volume 21 • Issue 5 • May 2016

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Received: Jun 9, 2015

Accepted: Dec 14, 2015

Published online: Mar 2, 2016

Published in print: May 1, 2016

Discussion open until: Aug 2, 2016

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C. C. Hodges, M.ASCE [email protected]

Graduate Research Assistant, Dept. of Civil and Environmental Engineering, Virginia Tech, 200 Patton Hall, Blacksburg, VA 24061 (corresponding author). E-mail: [email protected]

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W. M. McDonald, S.M.ASCE [email protected]

Graduate Research Assistant, Dept. of Civil and Environmental Engineering, Virginia Tech, 200 Patton Hall, Blacksburg, VA 24061. E-mail: [email protected]

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R. L. Dymond, M.ASCE [email protected]

Associate Professor, Dept. of Civil and Environmental Engineering, Virginia Tech, 200 Patton Hall, Blacksburg, VA 24061. E-mail: [email protected]

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K. L. Hancock, A.M.ASCE [email protected]

Associate Professor, Dept. of Civil and Environmental Engineering, Virginia Tech, 7054 Haycock Rd., Falls Church, VA 22043. E-mail: [email protected]

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Erratum for “Improved Methods of Parameterization for Estimating the Magnitude and Frequency of Peak Discharges in Rural Ungaged Streams” by C. C. Hodges, W. M. McDonald, R. L. Dymond, and K. L. Hancock

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